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kow [346]
3 years ago
9

How do us measure volume in science e.g if something is 14ml What is that in cm3 thanks

Physics
1 answer:
svlad2 [7]3 years ago
6 0
'ml' and 'cm³' are exactly the same volume, and they're both metric units.

If you're asking about volume measurements in the USA, then
fasten your seat belt.  It's going to be a bumpy ride:

-- 29.5735295625 ml makes 1 US fluid ounce

-- 8 US fluid ounces makes 1 US cup

-- 2 US cups makes 1 US pint (16 US fluid ounces)

-- 2 US pints makes 1 US quart (32 US fluid ounces, 4 US cups)

-- 4 US quarts makes 1 US gallon
(8 US pints, 16 US cups, 128 US fluid ounces, 231 cubic inches)




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It is gravity¿ what is the question?
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Mary was looking out of the window she saw lightening and then heard thunder a few seconds later explain why she saw lightening
alekssr [168]

Explanation:

It is based upon the fact that " The light travels faster then sound." As the speed of light is faster then the speed of sound, light travels 300,000 km per second and sound travels 1192 km per hour. That is why we observe the lightening first and hear the the sound of thunder later.

        You can do this experiment by yourself. Once you see the lightening start counting the seconds until you hear the sound of thunder.Then divide the seconds by 5, you will find out how many miles away the lightening strike was.

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3 years ago
A cat is moving at 18 m/s when it accelerates for 2 seconds. What is its acceleration?
vova2212 [387]

Answer: acceleration:4 m/s^{2}

              velocity: 26 m/s

Explanation:

The complete question is written bellow:

<em>A cat is moving at 18 m/s when it accelerates at </em>4 m/s^{2}<em> for 2 seconds. What is his new velocity?  </em>

<em />

In this situation the following equation will be useful:

V=V_{o}+at

Where:

V is the cat’s final velocity (new velocity)

V_{o}=18 m/s is the cat’s initial velocity

a=4 m/s^{2} is the cat's acceleration

t=2 s is the time

Solving the equation:

V=18 m/s+(4 m/s^{2})(2 s)

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5 0
3 years ago
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3 years ago
(11%) Problem 5: A uniform stationary ladder of length L = 2.7 m and mass M = 11 kg leans against a smooth vertical wall, while
jeka94

Answer:

970.2 N

Explanation:

We are given that

Length of ladder=2.7 m

Mass,M=11 kg

Coefficient of friction=\mu=0.45

\theta=51^{\circ}

Mass of painter=8M

Distance from base=d

We have to find the magnitude of the normal force exerted by the floor on the ladder.

Normal force exerted by floor on the ladder=mg+8mg=9mg

Where g=9.8m/s^2

Normal force exerted by floor on the ladder=9\times 11\times 9.8=970.2N

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3 years ago
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