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Temka [501]
3 years ago
15

Pls pls pls answer fast​

Physics
1 answer:
son4ous [18]3 years ago
5 0

Answer:

a) The maximum speed of the bus is 10 m/s

b) The bus was stationary for 3 seconds

c) The total distance travelled is about 126 m

d) The average velocity of the bus is approximately 5.04 m/s

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what volume of alcohol will have the same mass as 4.2m^3 of petrol? (density of alcohol 0.4kg/m^3 and petrol is 0.3kg/m^3)​
Alexxx [7]

Answer:

3.15m³

Explanation:

To solve this problem, let us first find the mass of the petrol from the given dimension.

       Mass  = density x volume

Volume of petrol  = 4.2m³

Density of petrol  = 0.3kgm⁻³  

       Mass of petrol  = 4.2 x 0.3  = 1.26kg

So;

      We can now find the volume of the alcohol

 Volume of alcohol = \frac{mass}{density}  

Mass of alcohol  = 1.26kg

Density of alcohol  = 0.4kgm⁻³  

  Volume of alcohol  = \frac{1.26}{0.4}   = 3.15m³

7 0
3 years ago
What is the speed of a bird of mass 8kg which has kinetic energy of 8836J?
Natali [406]

Answer:

i dont know

Explanation:

8 0
3 years ago
Runner x starts 50 feet in front of runner z and moves with a velocity of 8.0 m/s. At what speed would runner z have to run to c
Mariulka [41]

Answer:

15.625

Explanation:

8 0
3 years ago
One day on her walk home from school, Leann noticed some rust on an old car Leann knows that when iron and oxygen chemically rea
Katena32 [7]

Answer:

reactants

Explanation:

The reaction model is given as shown below:

                            4Fe   +   3O₂   →   2Fe₂O₃

The name that describes the iron and oxygen found on the left hand side of Leann's model is reactants.

Reactants in a chemical expression are the species that are combining together to give a product.

Some reactions only have one reactant and such a chemical process is often termed decomposition reaction.

The two moles of Fe₂O₃ is the product of the reaction.

4 0
3 years ago
A rectangular dam is 101 ft long and 54 ft high. If the water is 35 ft deep, find the force of the water on the dam (the density
blsea [12.9K]

To solve this problem we will begin by finding the pressure through density and average depth. Later we will find the Force, by means of the relation of the pressure and the area.

P = \rho h

Here,

h = Depth average

\rho = Density

Moreover,

\text{Density of water}= \rho = 62.4lb/ft^3

Replacing,

P = (62.4lb/ft^3)(\frac{35}{2}ft)

P = 1092 lb/ft^2

Finally the force

\text{Force} = \text{Pressure}\times \text{Area of dam with water acting on it}

F = 1092lb/ft^2(101ft*52ft)

F = 5.735*10^6lbf

6 0
3 years ago
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