What you do is you make it into a fraction. You got 60 out of 110, so that's 60<u />/110. Because all fractions are practically division problems, that's 60 ÷ 110 = 0.5454545454...
Times that by 100 to get the percentage.
Easy peasy
sub -4 for every x
f(-4)=3(-4)-5
f(-4)=-12-5
f(-4)=-17
answer is C
It's easiest to start with the point-slope form of an equation,
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
, where m is the slope and
![(x_1, y_1)](https://tex.z-dn.net/?f=%28x_1%2C%20y_1%29)
is the point given.
We have m = 3,
![x_1 = 5](https://tex.z-dn.net/?f=x_1%20%3D%205)
, and
![y_1 = 10](https://tex.z-dn.net/?f=y_1%20%3D%2010)
.
We plug in these values to get
![y-10=3(x-5)](https://tex.z-dn.net/?f=y-10%3D3%28x-5%29)
.
We now rearrange to get this into slope-intercept form,
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
, by solving for y.
Answer:
≈ 3.16 units
Step-by-step explanation:
To determine the distance between the two points, we need to use the distance formula. The distance formula states that;
![\sqrt{(x_{2} - x_{1})^{2} + (y_2 - y_1)^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%28x_%7B2%7D%20-%20x_%7B1%7D%29%5E%7B2%7D%20%2B%20%28y_2%20-%20y_1%29%5E%7B2%7D%20%20%7D)
Given coordinates;
When we substitute the coordinates into the formula, we get;
When we simplify the root, we get;
![\implies \sqrt{[-1]^{2} + [-8 + 5]^{2} }](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%7B%5B-1%5D%5E%7B2%7D%20%2B%20%5B-8%20%2B%205%5D%5E%7B2%7D%20%20%7D)
![\implies \sqrt{[-1]^{2} + [-3]^{2} }](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%7B%5B-1%5D%5E%7B2%7D%20%2B%20%5B-3%5D%5E%7B2%7D%20%20%7D)
![\implies \sqrt{1 +9 }](https://tex.z-dn.net/?f=%5Cimplies%20%5Csqrt%7B1%20%2B9%20%7D)
units ≈ 3.16 units (Using calculator)
Therefore, the distance between the points is about 3.16 units.