3\10 x 2\3 A.5\30 B.6\13 C.1\5 D.5\13
2 answers:
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Let X be the number of boys in n selected births. Let p be the probability of getting baby boy on selected birth.
Here n=10. Also the male and female births are equally likely it means chance of baby boy or girl is 1/2
P(Boy) = P(girl) =0.5
p =0.5
From given information we have n =10 fixed number of trials, p is probability of success which is constant for each trial . And each trial is independent of each other.
So X follows Binomial distribution with n=10 and p=0.5
The probability function of Binomial distribution for k number of success, x=k is given as
P(X=k) =
We have to find probability of getting 8 boys in n=10 births
P(X=8) =
= 45 * 0.0039 * 0.25
P(X = 8) = 0.0438
The probability of getting exactly 8 boys in selected 10 births is 0.044
Answer:
12
Because:
30 is to 25 as x is to 10.
As an equation: 30/25 = x/10
Do this equation by: look at image
