400/12 = # of dozen needed
.89 * # of dozen needed
400/12=33.33 need 34 dozen
.89*34=$30.26
Answer:
e^ (5 ln (x + 1)) = (x + 1)^5
Step-by-step explanation:
e5 In (x + 1) or did you mean e^ (5 ln (x + 1))
because then this would simplify a lot
e^ (5 ln (x + 1)) = e ^ (ln (x + 1)^5)
e^ (5 ln (x + 1)) = e ^ (ln (x + 1)^5) = (x + 1)^5
or did you mean (e^5) ( ln (x + 1)) = ln [(x+1)^(e^5)]
But I think you meant:
e^ (5 ln (x + 1)) = e ^ (ln (x + 1)^5) = (x + 1)^5
Answer:

Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>tips and formulas:</h3>
<h3>let's solve:</h3>




Answer:
0
Step-by-step explanation:
2a+ 2/a =4
Multiply each side by a to clear the fraction
a( 2a+ 2/a) =4*a
Distribute
2a^2 +2 = 4a
Subtract 4a from each side
2a^2 -4a +2 = 4a-4a
2a^2 -4a +2 =0
Divide by 2
2/2 a^2 -4a/2 +2/2 =0/2
a^2 -2a +1=0
Factor
(a-1) (a-1) =0
Using the zero product property
a=1
2a^2 -2/a^2
2(1)^2 -2/1^2
2-2
0
Answer:
105 is the larger of the two integers
Step-by-step explanation:
104+105=209
104 and 105 are consecutive and their sum is no more than 209