Given: ∠COR ≅ ∠WRO CO ∩ WR = N, CO = WR Prove: ∠C ≅ ∠W, RN = ON
1 answer:
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Answer:
The simplest form of is
Step-by-step explanation:
To add two algebraic fractions do these steps
- Factorize each denominator
- Simplify each fraction to its lowest term
- Find the LCM of the two denominators
- Divide LCM by each denominator and multiply the numerators by its corresponding quotients
- Add the two fraction and simplify the last answer
To simplify
Factorize each denominator
∵ The denominator of the first fraction is x² + 5x + 6
∵ x² = (x)(x)
∵ 6 = (2)(3)
∵ (2)(x) + (3)(x) = 5x ⇒ middle term
∴ x² + 5x + 6 = (x + 2)(x + 3)
∵ The denominator of the second fraction is x² + 3x + 2
∵ x² = (x)(x)
∵ 2 = (2)(1)
∵ (2)(x) + (1)(x) = 3x ⇒ middle term
∴ x² + 3x + 2 = (x + 2)(x + 1)
Find the LCM of the two denominators
∵ The denominators are (x + 2)(x + 3) and (x + 2)(x + 1)
- LCM is all the <u><em>different factors</em></u> multiplied together
∴ LCM of them is (x + 1)(x + 2)(x + 3)
- Divide LCM by each denominator
∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 3) = (x + 1)
- Multiply the numerator of the first fraction by (x + 1)
∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 1) = (x + 3)
- Multiply the numerator of the second fraction by (x + 3)
∴ =
- Add the numerators and write the answer as a single fraction
∴ =
- Factorize the numerator by taking 2 as a common factor
∵ 2x + 4 = 2(x + 2)
∴ =
- Simplify the fraction by dividing up and down by (x + 2)
∴ =
The simplest form of is
Answer:
The average is exactly 26,375 gallons of gas per hour.
How I found this is buy subtracting each numbers like 422,000 - 369,250 = 52,750. 369,250 - 316,500 = 52, 750 and so on. They all ended up being 52,750, but then I realized that they are all 2 hours apart and the question asks of gallons of gas per 1 hour so then I divided 52,750 in half and got my final answer, 26,375.
Step-by-step explanation:
This is how much gas the jet uses per 1 hour
my question doesn't ask me to create a linear model but it asks for gasoline per hour, and it's just like this question with the same graph so if you have the same as me this is the answer.
