Question

A computer takes 3x2 + 2 milliseconds to process a certain program. If the program has 4 lines of static code (this will always be required for the code to run) and x variable lines, what is the average amount of time it takes to process each line?

Answer 1

Answer:

Average time taken to process each line is $3x-12+\frac{50}{(x+4)}$ milliseconds

Step-by-step explanation:

A computer takes $3x^{2}$ + 2 milliseconds to process a certain program.

If the program has 4 lines of static code and x variable lines, then total lines to process will be

⇒ Total lines = (x + 4)

Now average amount of time to process each line = (Total time to process a program) ÷ (Total lines to process)

Average time = $\frac{3x^{2}+2}{x+4}$

                      = $3x-12+\frac{50}{(x+4)}$ milliseconds

So the answer is average time taken to process each line will be $3x-12+\frac{50}{(x+4)}$ milliseconds.

Answer 2

Solution:

Average time per line = total time / total lines

Average time per line = (3x^2 + 2)/(x + 4)

Average time per line = 3x - 12 + (3x^2 + 2)/50 milliseconds