The answer would be =<span>11/<span>20--Welcome , hopes this helps :P</span></span>
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
Angles ∠MOK and ∠NOL are identical by opposite angle theorem.
∠M = ∠N through given information
∠MKO and ∠NLO are congruent. Since the other two angles of each triangle are equivalent, the last angle must be equivalent to the last angle of the other triangle. (180 - ∠1 -∠2 = ∠3); you could also prove ∠MKO = ∠NLO by stating that the opposite sides of the two angles are congruent.
ΔMKO and ΔNLO by Angle-Angle-Side theorem
since ΔMKO and ΔNLO, all corresponding parts of both triangles are congruent, so therefore MO ≅ NO
1/3 divided by 5 and 1/3 x 1/5 are both correct
Answer:
6?
Step-by-step explanation:
