。☆✼★ ━━━━━━━━━━━━━━ ☾
You need to find the length of A F and BC first
Lets call BC --> 'x'
Lets form an equation
9 + 9 + x + x = 28
18 + 2x = 28
- 18
2x = 10
/ 2
x = 5
So now we have the length BC
We can subtract this length from the 11cm to find the vertical height of the trapezium
11 - 5 = 6
Now we have all we need to work it out.
area = (a + b) / 2 x h
area = (5 + 9) / 2 x 6
area = 42 cm^2
Have A Nice Day ❤
Stay Brainly! ヅ
- Ally ✧
。☆✼★ ━━━━━━━━━━━━━━ ☾
Yes as long as one side on a square is the same on another they are the copies of each other
The Perimeter of Triangle ABC would be 60.
You can solve this by setting up proportions.
The area of the circle is <span>112.98 m squared</span>