Question

A company specializing in building robots that can clean your house has found that the average amount of time kids spend cleaning their houses is about 2 hours per week. If their sample size was 1000 randomly chosen kids and the standard deviation was 0.3 hours, what is the margin of error for a confidence interval of 95%?

Answer 1

Answer:

0.588

Step-by-step explanation:

Margin of error is:

ME = CV × SE

where CV is the critical value (z score or t score), and SE is the standard error (standard deviation of the sample).

Since n is large, we can approximate as a normal distribution.  At 95% confidence level, z = 1.96.

Therefore, the margin of error is:

ME = 1.96 × 0.3

ME = 0.588