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Solnce55 [7]
3 years ago
10

Max is a professional table organizer. For today’s event, he brought square tables. A single square table can seat 4 people, one

at each side, as in the first picture below. If Max joins 2 tables along a side, as in the picture, he can seat 6 people. How many people can Max seat with even more tables?
Mathematics
1 answer:
AlexFokin [52]3 years ago
7 0

Answer:

The function would be 2(t)+2 where t is the number of tables. So, the answer in a form of a table would look like this:

Tables      People

1                4

2               6

3               8

4               10

5               12

Step-by-step explanation:

Khan Academy

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kathy plans to bake 2 types of cookies to take to the party. She needs to be sure she has enough ingredients. The chocolate chip
myrzilka [38]

Answer:

4 11/12

I hope I helped! (If I got it wrong, feel free to tell me I got it wrong)

7 0
3 years ago
What is the square root of 21
Andru [333]

Answer:

4.58

Step-by-step explanation:

21 is not a perfect square, but lies between the perfect squares 16 and 25.  Thus, √21 lies between √16 and √25, that is, between 4 and 5.  Since 21 is closer to 25 than to 16, √21 is closer to 5 than to 4.  A rough estimate of √21 would be 4.7.

√21 done on a calculator comes out to 4.58.

4 0
3 years ago
What can the intersection of a regular octagon and line segment be?
noname [10]

Answer:

See below

Step-by-step explanation:

Intersection of a regular octagon and a line segment can result in:

  • Triangle (ABC as example)
  • Quadrilateral (ABCD as example)
  • Pentagon (ABCDE as example)
  • Hexagon (ABCDEF as example)
  • Heptagon (ABCDEFG as example)

Refer to attached

8 0
3 years ago
Needhdjdjdjdjdjdnhiskdjdjdjdjdjdjjshdjdjdjdjdjdjdjd<br><br>​
Lilit [14]

9514 1404 393

Answer:

  -(√2)/2

Step-by-step explanation:

The expression evaluated at n=a gives the indeterminate form 0/0, so L'Hopital's rule can be used to find the limit. The second expression comes from differentiating numerator and denominator. Then the form with n=a is no longer indeterminate.

  \displaystyle\lim_{n\to a}{\frac{\sqrt{2n}-\sqrt{3n-a}}{\sqrt{n}-\sqrt{a}}}=\lim_{n\to a}{\frac{\frac{2}{2\sqrt{2n}}-\frac{3}{2\sqrt{3n-a}}}{\frac{1}{2\sqrt{n}}-0}}\\\\=\sqrt{a}\left(\frac{2}{\sqrt{2a}}-\frac{3}{\sqrt{3a-a}}}\right)=\boxed{-\frac{1}{\sqrt{2}}}

5 0
3 years ago
Find the difference and simplify the following<br> expressions.<br> (n – 8) – (2n + 2)
blagie [28]

Answer:

-n-10

Step-by-step explanation:

(n-8)-(2n+2)

n-8-(2n+2)

n-8-2n-2

-n-8-2

-n-10

4 0
3 years ago
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