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artcher [175]
4 years ago
15

Monty documented the amount of rain his farm received on a monthly basis, as shown in the table.

Mathematics
1 answer:
hammer [34]4 years ago
5 0

Answer:

No

Step-by-step explanation:

Because we need to see the table and information provided on the table otherwise we can't help you solve your problem.

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5) Solve 9x = 7x + 12
Nikolay [14]

Answer:

X=6

Step-by-step explanation:

Move the variable to get 9x-7x=12

collect like terms to get 2x=12

divide to get 6

6 0
3 years ago
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(13p5 + 6p - 12p2) - (-9p - p2 - 13p5)
anastassius [24]

Answer:

Step-by-step explanation:

13p⁵ + 6p - 12p² -(-9p - p² - 13p⁵) = 13p⁵ + 6p - 12p² + 9p + p² + 13p⁵

{Distribute  (-1) to the second expression}

= <u>13p⁵ + 13p⁵</u>    <u>-12p² + p²</u>     <u>+ 6p + 9p</u>

{Combine like terms}

= 26p⁵ - 11p² + 15p

7 0
3 years ago
15 is 60% of what number? please answer really soon!​
Anna35 [415]

Answer:25 hope this helps

Step-by-step explanation:

5 0
3 years ago
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Let f(x)=241+3e−1.3x . What is the point of maximum growth rate for the logistic function f(x) ? Round your answer to the neares
FromTheMoon [43]

Answer:

The point of maximum growth is at x=0.82

Step-by-step explanation:

Given a logistic function

f(x)=\frac{24}{1+e^{-1.3x}}

we have to find the point of maximum growth rate for the logistic function f(x).

From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at y=\frac{24}{2} i.e between 0 to 12

So, we can take y=\frac{24}{2} and then solve for x.

\frac{24}{2}=\frac{24}{1+e^{-1.3x}}

⇒ 2=1+3\exp{-1.3x}

⇒ 1=3.\exp{-1.3x} ⇒ \frac{1}{3}=\exp{-1.3x}

                             ⇒ log 3=-1.3x

                             ⇒ -0.4771=-1.3.x ⇒ x=0.82

Hence, the point of maximum growth is at x=0.82


5 0
4 years ago
((8x1.95) + (3x2.95) + 10.95) x 1.06
pychu [463]
The answer is 37.524 my friend
6 0
3 years ago
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