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Ilia_Sergeevich [38]

4 years ago

12

3x+1/5y=7 solve for y

1 answer:

Vladimir79 [104]4 years ago

5 0

Hello!

First, let's write the problem.
$3x+\frac{1}{5}y=7$
Subtract 3x from both sides.
$3x+\frac{1}{5}y-3x=7-3x$
$\frac{1}{5}y=7-3x$
The opposite of division is multiplication, so we are going to multiply in order to undo the fraction.
$5\cdot \frac{1}{5}y=5\cdot \:7-5\cdot \:3x$

Our final answer would be,
$y=35-15x$

Thanks!
-TetraFish

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Use this attachment to answer 1-3

nignag [31]

Simple,

1.) A vertical angle, is an angle directly across another angle. Thus, <2 and <5 are vertical angles.

2.)This is another pair of vertical angles, thus, m<4 is 53.

3.)Since m<1 is 50

You have the m<4 which is 50. You already have m<3 which is the right angle, 90.

Thus, 90+50=140

You know a line is supposed to be 180 degrees. So take,

180-140=40

Thus, the m<5 is 40.

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3 years ago

Plz Help!! <br><br> Factor the Polynomial: -6x² - 15x + 9

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Answer:

= -3(x+3)x(2x-1)

Step-by-step explanation:

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Step-by-step explanation:

Reduce 24/96 to lowest terms

Find the GCD (or HCF) of numerator and denominator. GCD of 24 and 96 is 24.

24 ÷ 2496 ÷ 24.

Reduced fraction: 14. Therefore, 24/96 simplified to lowest terms is 1/4.

7 0

3 years ago

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The dry cleaner fee for 3 pairs of pants is 18 doller what is the constant of proportionality

insens350 [35]

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3 years ago

Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

Solnce55 [7]

Answer:

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is $\mathbf{y=-\frac{2}{3}x+3 }$

Step-by-step explanation:

We need to Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

The equation in slope-intercept form is: $y=mx+b$ where m is slope and b is y-intercept.

Finding Slope:

The both equations given are parallel. So, they have same slope.

Slope of given equation y= - 2/3x is m = -2/3

This equation is in slope-intercept form, comparing with general equation $y=mx+b$ where m is slope , we get the value of m= -2/3

So, slope of required line is: m = -2/3

Finding y-intercept

Using slope m = -2/3 and point (-3,5) we can find y-intercept

$y=mx+b\\5=-\frac{2}{3}(-3)+b\\5=2+b\\ b=5-2\\b=3$

So, we get b = 3

Now, the equation of required line:

having slope m = -2/3 and y-intercept b =3

$y=mx+b\\y=-\frac{2}{3}x+3$

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is $\mathbf{y=-\frac{2}{3}x+3 }$

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3 years ago

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