Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Total value of ratio = 4+3+1 = 8
value of 1 unit = 64/8 = 8
numbers are 4(8), 3(8), 1(8) = 32, 24, 8
so, the greatest number is 32
Answer: 2 x - 3 y = 6 i think but let let me know if i'm wrong
Answer:
1418.03
Step-by-step explanation:
86.50 is 6.1% of what amount?
Multiply 86.50 x 100 = 8650
Divide by 6.1 = 1418.03
