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inn [45]
3 years ago
15

Descriptive statistics ___________, while inferential statistics ______________. are measures of central tendency; are measures

of variance summarize data; assess if data can be generalized describe data from experiments; describe data from surveys and case studies determine if data can be generalized to other populations; summarize data indicate the significance of the data; summarize the data
Mathematics
1 answer:
Leviafan [203]3 years ago
8 0

Answer:

Descriptive statistics <u>describe data from surveys and case studies,</u> while inferential statistics <u>determine if data can be generalized to other populations</u>.

Step-by-step explanation:

Let's look at the definition of each type of Statistics

Descriptive Statistics, as the name says, describes, properties or characteristics (that can be gathered through surveys and case studies), using mathematical methods for tendency and dispersion.

Inferential statistics, as the name states, infers, if samples from a larger data set have behaviors that can be then extrapolated to the larger group.

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Find the measure of the ndicaited angle to the nearest degree 35 and 38
12345 [234]

The measure of the indicated angle to the nearest degrees is 23 degrees.

<h3>How to find angle of a right angle triangle?</h3>

The angle of a right angle triangle can be found as follows:

Therefore, the angle can be found using trigonometric ratios as follows;

cos ∅ = adjacent / hypotenuse

Therefore,

adjacent side = 35 units

hypotenuse side = 38 units

Hence,

cos ∅ = 35 / 38

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∅ = 22.9272842944

∅ ≈ 23 degrees.

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1 year ago
A wood board 156 centimeters long is cut into three parts .The two longer parts are the same length and are 15 centimeters longe
n200080 [17]
The everyone of two longer parts has 57 cm length and the shortest part has 42 cm length.
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6 0
3 years ago
Need help on this calculus
N76 [4]
\displaystyle\int\sin^3t\cos^3t\,\mathrm dt

One thing you could do is to expand either a factor of \sin^2t or \cos^2t, then expand the integrand. I'll do the first.

You have

\sin^2t=1-\cos^2t

which means the integral is equivalent to

\displaystyle\int\sin t(1-\cos^2t)\cos^3t\,\mathrm dt

Substitute u=\cos t, so that \mathrm du=-\sin t\,\mathrm dt. This makes it so that the integral above can be rewritten in terms of u as

\displaystyle-\int(1-u^2)u^3\,\mathrm du=\int(u^5-u^3)\,\mathrm du

Now just use the power rule:

\displaystyle\int(u^5-u^3)\,\mathrm du=\dfrac16u^6-\dfrac14u^4+C

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4 0
2 years ago
Read 2 more answers
A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)ln(5t). Find the acceleration of the par
lyudmila [28]

Answer:

a(\frac{1}{5e})=5e

Step-by-step explanation:

we are given equation for position function as

s(t)=tln(5t)

Since, we have to find acceleration

For finding acceleration , we will find second derivative

s'(t)=\frac{d}{dt}\left(t\ln \left(5t\right)\right)

=\frac{d}{dt}\left(t\right)\ln \left(5t\right)+\frac{d}{dt}\left(\ln \left(5t\right)\right)t

=1\cdot \ln \left(5t\right)+\frac{1}{t}t

s'(t)=\ln \left(5t\right)+1

now, we can find derivative again

s''(t)=\frac{d}{dt}\left(\ln \left(5t\right)+1\right)

=\frac{d}{dt}\left(\ln \left(5t\right)\right)+\frac{d}{dt}\left(1\right)

=\frac{1}{t}+0

a(t)=\frac{1}{t}

Firstly, we will set velocity =0

and then we can solve for t

v(t)=s'(t)=\ln \left(5t\right)+1=0

we get

t=\frac{1}{5e}

now, we can plug that into acceleration

and we get

a(\frac{1}{5e})=\frac{1}{\frac{1}{5e}}

a(\frac{1}{5e})=5e


5 0
3 years ago
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