3 years ago

Plz help me with the answer

Mathematics

1 answer:

Tems11 [23]3 years ago

8 0

Answer:

Step-by-step explanation:

$-\dfrac{1}{5}x3\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{1}{5\!\!\!\!\diagup_1}x$

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The value of integration of y=16- $x^{2}$ from x=-1 to x=1 is 94/3.

Given the equation y=16- $x^{2}$ and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16- $x^{2}$ from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16- $x^{2}$

Find the integration of 16- $x^{2}$ .

=16x- $x^{3}/3$

Now find the value of integration from x=-1 to x=1.

=16(1)- $(1)^{3}/3$ -16(-1)- $(-1)^{3}/3$

=16(1)-1/3+16-1/3

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=94/3

Hence the value of integration of y=16- $x^{2}$ from x=-1 to x=1 is 94/3.

Learn more about integration at brainly.com/question/27419605

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