Answer:
Step-by-step explanation:
<h2><u>Part A</u></h2>
in interval ( 0 ; 2)
<h2><u>Part B</u></h2>
in interval (2; 4)
<h2><u>Part C</u></h2>
in interval (4 ; 6 )
<h2><u>Part D</u></h2>
The graph shows that at first the ball rises up ; and then it is seen that it goes down and loses height to zero , from which it can be concluded that the height after 10 seconds remains unchanged and therefore the height of the ball after 16 seconds will be zero
Answer:
Give me a question to answer
Answer:
<h2>-33x - 82</h2>
Step-by-step explanation:
Use
PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
and the distributive property a(b + c) = ab + ac.
![1)\qquad5(x+3)=5x+15\\\\2)\qquad x+5(x+3)=x+5x+15=6x+15\\\\3)\qquad2[x+5(x+3)]=2(6x+15)=12x+30\\\\4)\qquad x-2[x+5(x+3)]=x-(12x+30)=x-12x-30=-11x-30\\\\5)\qquad3\{x-2[x+5(x+3)]\}=3(-11x-30)=-33x-90\\\\6)\qquad8+3\{x-2[x+5(x+3)]\}=8+(-33x-90)=-33x-82](https://tex.z-dn.net/?f=1%29%5Cqquad5%28x%2B3%29%3D5x%2B15%5C%5C%5C%5C2%29%5Cqquad%20x%2B5%28x%2B3%29%3Dx%2B5x%2B15%3D6x%2B15%5C%5C%5C%5C3%29%5Cqquad2%5Bx%2B5%28x%2B3%29%5D%3D2%286x%2B15%29%3D12x%2B30%5C%5C%5C%5C4%29%5Cqquad%20x-2%5Bx%2B5%28x%2B3%29%5D%3Dx-%2812x%2B30%29%3Dx-12x-30%3D-11x-30%5C%5C%5C%5C5%29%5Cqquad3%5C%7Bx-2%5Bx%2B5%28x%2B3%29%5D%5C%7D%3D3%28-11x-30%29%3D-33x-90%5C%5C%5C%5C6%29%5Cqquad8%2B3%5C%7Bx-2%5Bx%2B5%28x%2B3%29%5D%5C%7D%3D8%2B%28-33x-90%29%3D-33x-82)
3 pints every four minutes.(3+1=4)
2 pints every 3 minutes.(2+1=3)
What I realised was that the difference is 1 pint every minute.
8*.8=6.4
4x+6.4=40
40-6.4=33.6
33.6/4=x
8.4=x
Hope this helps :)
