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Novosadov [1.4K]
3 years ago
6

A building 50ft tall is on top of a hill A surveyor is at a point on the hill and observes that the angle of elevation to the to

p of the
building measures 48° and to the bottom of the building is 20°. How far is the surveyor from the bottom of the building?
Mathematics
2 answers:
kenny6666 [7]3 years ago
6 0

Answer:

the answer is the difference of 48-20

Step-by-step explanation:

suter [353]3 years ago
3 0

Answer:

48-20

Step-by-step explanation:

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HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!<br> Show your work
cestrela7 [59]
Well start with reflecting abc over the y axis
7 0
3 years ago
You have a choice between 2 jobs, one pays $8.25/hr but requires you to spend $20 to get a uniform. The other pays $7.50/hr. At
Veronika [31]

Step-by-step explanation + Answer:

x = 1st job

y = 2nd job

x + y = 22......x = 22 - y

7x + 8.25y = 171.50

7(22 - y ) + 8.25y = 171.50

154 - 7y + 8.25y = 171.50

-7y + 8.25y = 171.50 - 154

1.25y = 17.50

y = 17.50 / 1.25

y = 14 <== 14 hrs at the 8.25 per hr job

x + y = 22

x + 14 = 22

x = 22 - 14

x = 8 <=== 8 hrs at the 7 per hr job

5 0
1 year ago
Write the equation 2x - 3y = 6 in slope-intercept form.
ExtremeBDS [4]

Answer:

y =  \frac{  2}{ 3} x  - 2

Step-by-step explanation:

2x - 3y = 6 \\  - 3y =  - 2x + 6 \\  \\ y =  \frac{ - 2}{ - 3} x +  \frac{6}{ - 3}  \\  \\ \huge \purple{ \boxed{ y =  \frac{  2}{ 3} x  - 2}} \\ this \: is \: in \: the \: slope - intercept \: form.

5 0
3 years ago
Read 2 more answers
The product of 3.41 and 8.5 will have how many decimal places?
Aleks04 [339]
Hello! 

3.41 × 8.5 = 28.985

The product of 3.41 and 8.5 is 28.985, which has three decimal places. 

3 0
3 years ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
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