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nevsk [136]
3 years ago
9

At the local pet store, zebra fish cost $1.85 each and neon tetras cost $2.10 each. If Yumi bought 11 fish for a total cost of $

21.60, not including tax, how many of each type of fish did she buy?
A 7 zebra fish, 4 neon tetras
B 4 zebra fish, 7 neon tetras
C 6 zebra fish, 5 neon tetras
D 5 zebra fish, 6 neon tetras
Mathematics
1 answer:
Amanda [17]3 years ago
5 0

Answer: C. 6 zebra fish, 5 neon tetras. Is $21.60

Step-by-step explanation:

1.85 • 6 = 11.10

2.10 • 5 = 10.50

11.10 + 10.50 = 21.60

$21.60

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Maya sells candles to her 5 neighbors. Each neighbor buys 2 boxes of candles. There are 6 candles in each box. What is the total
DedPeter [7]

Answer:

Each neighbor will get 12 candles so in total, 60 candles will be sold.

Step-by-step explanation:

7 0
3 years ago
john found a pair of jeans that cost $55.00. If he had a 10%-off coupon, how much would the jeans cost?
mash [69]
THE ANSWER IS 49.50

Because if you divide 55 and 10 it gives you 5.5. So with that answer you just subtract to the price of the jeans giving you 49.50
6 0
3 years ago
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The net worthw(t) of a company is growing at a rate of′(t) = 2000−121t2dollarsper year, wheretis in years since 1990.(a) If the
stiv31 [10]

Answer:

The worth of the company in 2000 is $56,000.

Step-by-step explanation:

The growth rate of the company is:

f'(t)=2000-12t^{2}

To determine the worth of the company in 2000, first compute the change in the net worth during the period 1990 (<em>t</em> = 0) to 2000 (<em>t</em> = 10) as follows:

\int\limits^{10}_{0} {2000-12t^{2}} \, dt =\int\limits^{10}_{0} {2000} \, dt-12\int\limits^{10}_{0} {t^{2}} \, dt=2000 |t|^{10}_{0}-12|\frac{t^{3}}{3}|^{10}_{0}\\=(2000\times10)-(4\times10^{3})\\=20000-4000\\=16000

The increase in the company's net worth from 1990 to 2000 is $16,000.

If the company's worth was $40,000 in 1990 then the worth of the company in 2000 is:

Worth in 2000 = Worth in 1990 + Net increase in company's worth

                        =40000+16000\\=56000

Thus, the worth of the company in 2000 is $56,000.

4 0
3 years ago
Find a8 when a1 = 40,000, r = 0.1
Sindrei [870]

Answer:

a8 = 0.004

Step-by-step explanation:

Q is abt a geometric series given by the eqn: an = a1*r^(n-1)

given a1 = 40000, r = 0.1

an = 40000*(0.1)^(n-1)

a8 = 40000*(0.1)^(8-1)

= 40000*(0.1)^7

= 0.004


3 0
3 years ago
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Plzz help!!!!<br><br> Which set of ordered pairs corresponds to the graph?
adelina 88 [10]

Answer:

Option 3rd is correct

Step-by-step explanation:

(1,-6),(2,-4),(2,-2),(4,-2),(6,0)

5 0
3 years ago
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