Question

Here are the first five terms of a number sequenceS . 10 16 22 28 34 Find an expression, in terms of n , for the nth term of this sequence.

Answer 1

Answer:

t = 4 + 6n

Step-by-step explanation:

a = 10

d = 6

in general

tn = a + (n-1)*d

tn = 10 + (n-1)*6

tn = 10 + 6n - 6

tn = 4 + 6n

So if n = 5 then

t5 = 4 + 6*5

t5 = 4 + 30

t5 = 34 which agrees with your givens.