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3 years ago

What is the image of (3,-12) after a dilation by a scale factor of 1/3 centered at the origin?

Mathematics

2 answers:

Montano1993 [528]3 years ago

7 0

Answer:

(1, -4)

Step-by-step explanation:

With what you gave, that's the reduction.

ICE Princess25 [194]3 years ago

6 0

(1, -4) is the correct answer buddy :)

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3 years ago

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ss7ja [257]

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3 years ago

Read 2 more answers

Two cars left the city for a suburb, 480 km away, at the same time. The speed of one of the cars was 20 km/hour greater than the

Alex_Xolod [135]

The speed of both the cars are 80km/h and 60km/h

Step-by-step explanation:

Let the speed of one car be 'a' and the speed of other car be 'b'.

The total distance (d) = 480km

It is given that the speed of one car is 20km/h faster than the other.

We can write,

a = b+20

The slower car takes 2 hrs more to reach the suburb than the other car.

Let the time taken by the fastest car be t

Speed = distance/time

So,

a = 480/ t

b = 480/(t+2)

We got the values of a and b.

a = b+20

480/t = (480/(t+2)) + 20

Taking LCM on the right side.

480/t = (480 + 20t + 40) / (t+2)

480(t+2) = (480+20t+40) t

480t + 960 = 480t + 20t(t) + 40t

20t(t) + 40t - 960 = 0

Divide the whole equation by 20 to simplify the equation.

t(t) + 2t - 48 = 0

Solve the quadratic equation by splitting the middle terms.

t(t) + 8t - 6t - 48 = 0

t(t + 8) - 6(t + 8) = 0

(t- 6) (t+8) =0

t = 6 (or) -8

t is time and cannot be negative. So t= 6hrs

a = 480/t

a = 480/ 6 = 80

the speed of the fastest car is 80km/hr

a = b + 20

b = a - 20

b = 80 - 20

b = 60km/h

4 0

3 years ago

the variables a and B are positive numbers. drag and drop each coordinate point to match the correct quadrant.

inessss [21]

Answer:

Hence,

Quadrant I --------------- ( a , b)

Quadrant II --------------- ( -a , b)

Quadrant III --------------- ( -a , -b)

Quadrant IV --------------- ( a , -b)

Step-by-step explanation:

There our four quadrant divided by the x-axis and y-axis.

So the variables according to the quadrant are given below.

Quadrant I : Both the coordinates are positive.

Quadrant II : x-coordinate is negative and y-coordinate it is positive.

Quadrant III : x-coordinate is negative and y-coordinate it is negative.

Quadrant IV : x-coordinate is positive and y-coordinate it is negative.

Hence,

Quadrant I --------------- ( a , b)

Quadrant II --------------- ( -a , b)

Quadrant III --------------- ( -a , -b)

Quadrant IV --------------- ( a , -b)

6 0

4 years ago

If a^2+1/a^2=79 where (a>0), find the value of a^3 +1/a^3

Nastasia [14]

Note the binomial expansion,

(a + 1/a)³ = a ³ + 3a + 3/a + 1/a ³

a ³ + 1/a ³ = (a + 1/a)³ - 3 (a + 1/a)

Similarly,

(a + 1/a)² = a ² + 2 + 1/a ²

We're given a ² + 1/a ² = 79, so

(a + 1/a)² - 2 = 79

(a + 1/a)² = 81

a + 1/a = ±9

but a > 0, so we ignore the negative solution.

Then

a ³ + 1/a ³ = 9³ - 3×9 = 702

7 0

3 years ago

What is the image of (3,-12) after a dilation by a scale factor of 1/3 centered at the origin?​

What is the image of (3,-12) after a dilation by a scale factor of 1/3 centered at the origin?