Answer:
9. 
8. 
7. 
Step-by-step explanation:
![\displaystyle [x - h]^2 - [y - k]^2 = r^2 → Hyperbola\:Equation \\ [x - h]^2 + [y - k]^2 = r^2 → Circle\:Equation \\ [h, k] → Centre](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Bx%20-%20h%5D%5E2%20-%20%5By%20-%20k%5D%5E2%20%3D%20r%5E2%20%E2%86%92%20Hyperbola%5C%3AEquation%20%5C%5C%20%5Bx%20-%20h%5D%5E2%20%2B%20%5By%20-%20k%5D%5E2%20%3D%20r%5E2%20%E2%86%92%20Circle%5C%3AEquation%20%5C%5C%20%5Bh%2C%20k%5D%20%E2%86%92%20Centre)
According to the equations in the exercises, in the parentheses, ALL NEGATIVE SIGNS give the OPPOSITE terms of what they REALLY are, so be EXTREMELY CAREFUL with your translations:
9. [4, 11]
+ 3 + 4
_____
[7, 15] → (x - 7)² and (y - 15)²
8. [−2, 8]
+ 3 + 2
_____
[1, 10] → (x - 1)² and (y - 10)²
7. [−8, −14]
+ 3 - 5
______
[−5, −19] → (x + 5)² and (y + 19)²
** NOTISE THAT THE RADII <em>NEVER</em><em> </em>ALTER.
I am joyous to assist you anytime.
Answer:
3y+5x=0
Step-by-step explanation:
The question is on equations of parallel lines
Finding the gradient m of line AB
m=change in y coordinates/change in x-co-ordinates
Given points A(-3,0) and B (-6,5)
m=Δy/Δx Δy=5-0=5 Δx=-6 - -3= -3 ⇒m= - 5/3
Equation
The line will have its gradient equal to - 5/3
m=-5/3
point is the origin (0,0)
m=Δy/Δx
y-0/x-0 = -5/3
3(y-0)=-5(x-0)
3y-0= -5x+0
3y=-5x
3y+5x=0
Combine the fractions by finding a common denominator.
1/25 or 0.04
The circle equation is in the format (x – h)² + (y – k)² = r², with the center being at the point (h, k) and the radius being "r".
QUESTION 11.
Equation x²+y²+10x-14y-7 =0 can be rewritten as: x²+10x+25 + y² -14y + 49 -7 - 25 - 49=0
It can be factories as (x + 5)² + (y – 7)² = 9²
Therefore the radius equals 9 and the center is (-5,7)
QUESTION 12.
From equation (x + 4)² + y² = 121
The radius equals √121 = 11 and the center is (-4,0)
QUESTION 13.
As there are missing information in the question, I can't assist. However, you can use the general circle equation (x – h)² + (y – k)² = r² to solve the question.
Finally equations 14 & 15 aren't linear.
Hope that helps you :)
You need to tell me the side lengths. to be able to find the height you fool!<span />
