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3 years ago

6

kevin is making a banner with an area of 7 square feet. the width and length of the banner are whole numbers. what are its possi

ble dimensions

1 answer:

Helga [31]3 years ago

5 0

There are no two whole numbers that multiply to 7. Multiplication is how you get an area on 2D items. 7 is a prime number.

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Mr.Williams, a parking lot owner, sold 20% of his lot to his neighbor. Later that year he sold 20% of the remainder of his lot t

riadik2000 [5.3K]

Answer: He still owns 64% of the Mr.Williams' original parking.

Step-by-step explanation:

Let x = Area of the original parking plot.

First he sold 20% of his lot to neighbor .

Sold plot = 20% of x = 0.20x [Replace 'of' by '×' and divide number by 100 to remove %]

Reminder= x-0.20x= (1-0.20)x=0.80x

Again he sold 20% of the remainder .

Sold plot = 20% of (0.80x) = 0.20 (0.80x)

= 0.16x

Remainder plot = 0.80x-0.16x= 0.64x

Percent of Mr.Williams' original parking lot does he still own = $\dfrac{0.64x}{x}\times100=64\%$

Hence, he still owns 64% of the Mr.Williams' original parking.

4 0

3 years ago

A manufacturer of coffee vending machines has designed a new, less expensive machine. The current machine is known to dispense (

cupoosta [38]

Answer:

$t=(15-1) [\frac{0.219}{0.2}]^2 =16.7864$

$p_v = 2*P(\chi^2_{14}>16.786)=0.5355$

And the 2 is because we are conducting a bilateral test.

$\alpha=0.05$ since the the $p_v >0.05$ we fail to reject the null hypothesis.

$\alpha=0.01$ since the the $p_v >0.01$ we fail to reject the null hypothesis.

Step-by-step explanation:

Data given

$\mu=7$ population mean (variable of interest)

$\sigma=0.2$ represent the population standard deviation

$s=0.219$ represent the sample deviation

n=15 represent the sample size

$\alpha=0.05,0.01$ represent the values for the significance level

Hypothesis test

On this case we want to check if the population standard deviation is equal or not to 0.2, so the system of hypothesis are:

H0: $\sigma = 0.2$

H1: $\sigma \neq 0.2$

In order to check the hypothesis we need to calculate the statistic given by the following formula:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

$t=(15-1) [\frac{0.219}{0.2}]^2 =16.7864$

P value

We know the degrees of freedom of the distribution 14 on this case and we can find the p value like this:

$p_v = 2*P(\chi^2_{14}>16.786)=0.5355$

And the 2 is because we are conducting a bilateral test.

$\alpha=0.05$ since the the $p_v >0.05$ we fail to reject the null hypothesis.

$\alpha=0.01$ since the the $p_v >0.01$ we fail to reject the null hypothesis.

3 0

3 years ago

What number is 10 more than 237

xxTIMURxx [149]

247 is 10 more than 237

5 0

3 years ago

Read 2 more answers

The Difference of 9 and y is greater than or equal to 14

Viktor [21]

Answer:

$9 - y \geqslant 14$

hoped that helped

7 0

3 years ago

Read 2 more answers

Find the product. Write your answer in exponential form. <br><br> 5^5•5

Karo-lina-s [1.5K]

Answer:

5^6

Step-by-step explanation:

5^5×5 = 5^5×5^1 = 5^(5+1) = 5^6

_____

This may become more obvious if you remember that an exponent signifies repeated multiplication:

(5^5)·(5) = (5·5·5·5·5)·(5) = 5·5·5·5·5·5 = 5^6

5 0

3 years ago