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g100num [7]
3 years ago
12

A number that has a digit in the tenths place,hundredths place,or beyond

Mathematics
1 answer:
nadya68 [22]3 years ago
4 0
A number that has a digit in the tenths place, hundredths place or beyond is called decimal numbers. Any number after the decimal point is called decimal number, it value always started in tenths place value, then followed by hundredths, then thousandths, then ten thousandths, then hundred thousandths and so on. It is still the same with giving place value in whole number. The only difference is, its value decreases as it becomes away from the decimal point.
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Use division instead of the images to divide 18 by 4. What is the quotient of the division? What is the remainder?
musickatia [10]

18 \div 4
First see what 4 could go by and the answer closest to 18 that is not more than the answer is the first number of the answer.
4×1=4
4×2=8
4×3=12
4×4=16
In this case 4 is the first number of the answer because if you fo 4 by 5 it equals 20 , which is more than the answer
4×5=20
after that , you subtract the answer, 18 minus 16 which is 2 because nothing times 4 equals 2
So the remainder is 2/4 or .50
If you have any questions about this please don't hesitate to ask me

4 0
4 years ago
(1/4)x+1=32 <br><br> -A: -7/2<br> -B: 2<br> -C: -2<br> -D: 3/2
777dan777 [17]
The answer is b due to pemdas
4 0
3 years ago
What is the equivalent fraction for 1/2​
allochka39001 [22]
It could be:

2/4
4/8
8/16
3/6
5/10
6/12
6 0
3 years ago
Read 2 more answers
Plssss help me with this thx im not good at math
Marina CMI [18]
The answer is c 25 minutes btw hope you have a wonderful day
8 0
3 years ago
a. Calculate the volume of the solid of revolution created by rotating the curve y = 3 + 3 exp(-5 x) about the x-axis, for x bet
miskamm [114]

Answer:

A) The volume of solid is 18π cubic unit.

B) The volume of sphere is \dfrac{4}{3}\pi r^3

    a = -r , b = r , f(x)=\sqrt{r^2-x^2} and V=\dfrac{4}{3}\pi r^3

Solution A)

The given curve, y=3+3e^{-5x} rotate about x-axis between 2 to 4.

Please find attachment for solid figure or rotation.

Using disk method to find the volume rotation about x-axis

V=\int_a^b\pi R^2dx  

where, a = 2, b= 4 , R=y=3+3e^{-5x} and dx is thickness of disk.

V=\int_2^4\pi (3+3e^{-5x})^2dx

V=9\pi\int_2^4(1+e^{-10x}+2e^{-5x})dx

V=9\pi(x-\dfrac{1}{10}e^{-10x}-\dfrac{2}{5}e^{-5x})|_2^4)

V=9\pi(4-\dfrac{1}{10}e^{-40}-\dfrac{2}{5}e^{-20}-2+\dfrac{1}{10}e^{-20}-\dfrac{2}{5}e^{-10}))

V=9\pi (2-0)

V=18\pi

Hence, the volume of solid is 18π cubic unit

Solution B)

The equation of circle of radius r and centered at origin (0,0).

x^2+y^2=r^2

y=\sqrt{r^2-x^2}

The solid form is sphere of radius r.

Using disk method, to find volume of solid

V=\int_a^b\pi R^2dx  

where, a = -r, b = r , R=y=\sqrt{r^2-x^2} and dx is thickness of disk.

V=\int_{-r}^r\pi (r^2-x^2)dx

V=\pi(r^2x-\dfrac{x^3}{3})|_{-r}^r

V=\pi(2r^3-\dfrac{2r^3}{3})

V=\dfrac{4}{3}\pi r^3

Hence, the volume of sphere is \dfrac{4}{3}\pi r^3

4 0
4 years ago
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