Please help me asap. Prove that: Sin(A+B).Sin(A-B)=Sin²A.Sin²B
2 answers:
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Answer:
13, 14
Step-by-step explanation:
The parameters of the numbers are;
A whole number value = 2 × Another number + 6
The sum of the two numbers is less than 50
Given that the first number is equal to more than twice the second number, we have that the first number is the larger number, while the second number is the smaller number
Where 'x' represents the second number, we get;
x + 2·x + 6 < 50
Simplifying gives;
3·x + 6 < 50
x < (50 - 6)/3 = 14.
x < 14.
Therefore, the numbers for which the inequality holds true are numbers less than 14.. From the given option, the numbers are 13, and 14.
Subtract 13 from both sides:
Divide both sides by -5. Since this is a negative number, you have to invert the inequality sign:
Which means
The answer is 7.21...
