What is -37c on the Fahrenheit scale

A golf club is swung and strikes a golf ball with a force of 12.2 N. The golf ball accelerates at 265.2 m/s2 (wow) Determine the

Sunny_sXe [5.5K]

F = m A (Newton #2)

m = F/A

m = (12.2 N) / (265.2 m/s²)

m = (12.2 / 265.2) kg

(46 grams; not bad; the international standard is "not more than 45.93 grams")

Note: 265.2 m/s² = about 27 G's . Seems to me like that would rip the ball to shreds, but I don't really know anything about golf.)

7 0

3 years ago

Which element can form straight chains, branched chains, and rings

Mice21 [21]

Carbon atoms can form straight, and branched chains, and rings

6 0

3 years ago

Read 2 more answers

A red laser from the physics lab is marked as producing 632.8-nm light. When light from this laser falls on two closely spaced s

BARSIC [14]

Answer:

The wavelength is $\lambda_R = 649 *10^{-9}\ m$

Explanation:

From the question we are told that

The wavelength of the red laser is $\lambda_r = 632.8 \ nm = 632.8 *10^{-9}\ m$

The spacing between the fringe is $y_r = 6.00\ mm = 6.00*10^{-3} \ m$

The spacing between the fringe for smaller laser point is $y_R = 6.19 \ mm = 6.19 *10^{-3} \ m$

Generally the spacing between the fringe is mathematically represented as

$y = \frac{D * \lambda }{d}$

Here $D$ is the distance to the screen

and d is the distance of the slit separation

Now for both laser red light light and small laser point D and d are same for this experiment

So

$\frac{y_r}{\lambda_r} = \frac{D}{d}$

=> $\frac{y_r}{\lambda_r} = \frac{y_R}{\lambda_R}$

Where $\lambda_R$ is the wavelength produced by the small laser pointer

So

$\frac{6.0 *10^{-3}}{ 632.8*10^{-9}} = \frac{ 6.15 *10^{-9}}{\lambda_R}$

=> $\lambda_R = 649 *10^{-9}\ m$

7 0

3 years ago

A skier is traveling fast down a mountain slope. The table shows data

melisa1 [442]

Answer:

The pushing force and the skier's mass

(A) is correct option.

Explanation:

Given that,

Mass = 64 kg

Weight = 608 N

Velocity = 21 m/s

Forward force = 45 N

We need to calculate the reaction force of the snow pushing on the skier

Using given data,

The reaction force of the snow pushing on the skier is equal to the pushing force and the skier's mass.

Hence, The pushing force and the skier's mass

(A) is correct option.

6 0

3 years ago

The object has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 microme-

olasank [31]

b. The wavelength of light emitted by the object is 233 nm

c. The type of radiation originally emitted by the object is ultraviolet radiation.

To find the wavelength, we need to know what redshift is.

<h3>What is redshift?</h3>

Redshift is the increase in wavelength and the corresponding decrease of frequency and photon energy of electromagnetic radiation.

Redshift is given by z = λ'/λ - 1 where

λ' = observed wavelength and
λ = emitted wavelength.

Making λ subject of the formula, we have

λ = λ'/(1 + z)

Given that has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 micrometres (mid-infrared light).

So,

z = 7.6 and
λ' = 2μm

<h3>(b) What is the wavelength of the light emitted by the object?</h3>

Substituting the values of the variables into the equation, we have

λ = λ'/(1 + z)

λ = 2μm/(1 + 7.6)

λ = 2μm/8.6

λ = 0.233 μm

λ = 233 nm

So, the wavelength of light emitted by the object is 233 nm

<h3>c. What type of radiation was originally emitted by the object?</h3>

Since the wavelength is 233 nm and the wavelength is in the range of ultraviolet radiation 200 nm - 315 nm.

So, the type of radiation originally emitted by the object is ultraviolet radiation.

Learn more about redshift here:

brainly.com/question/27915180

#SPJ1

8 0

3 years ago