Question

Determine the inductance of a solenoid with 650 turns in a length of 28 cm . The circular cross section of the solenoid has a radius of 3.5 cm .

Answer 1

Answer:

The value is $L = 0.0073 \ H$      

Explanation:

From the question we are told that

    The number of turns is  $N = 650 \ turns$

     The length is  $l = 28 \ cm = 0.28 \ m$

      The radius of the cross-section is $r = 3.5 \ cm = 0.035 \ m$

Generally the cross-sectional area  is mathematically represented as

       $A = \pi * r^2$

=>    $A = 3.142 * 0.035^2$

=>    $A = 0.00384 \ m^2$

Generally the inductance is mathematically represented as

      $L = \frac{N^2 * \mu _o * A }{ l}$

Here  $\mu_o$ is the permeability of free space with value $\mu_o = 4\pi * 10^{-7} N/A^2$

=>    $L = \frac{ 650^2 * 4\pi * 10^{-7} * 0.00384 }{0.28}$

=>    $L = 0.0073 \ H$