Answer: The velocity is 21.5m/s
Explanation:
Let's call:
M1 and V1 as the mass and velocity of the falcon:
M1 = 1.45kg
V1 = 26.5m/s
M2 and V2 as the mass and velocity of the dove:
M2 = 0.415kg
V2 = 4.35m/s
Where both velocities are positive because both animals move in the same direction.
We can think that the interaction between both animals is a perfectly inelastic collision, because afther the interaction they move as one. Then, we have that the final velocity of both animals togheter is:
V = (V1*M1 + V2*M2)/(M1 + M2)
V = (1.45kg*26.5m/s + 0.415kg*4.35m/s)/(1.45kg + 0.415kg) = 21.5m/s
E = 0.25 = m*g*h
<span>h = 0.25/(m*g) = 0.25/(0.125*10) = 0.25/1.25 = 1/5 = 0.20 m
I hope this helps you have a great day and im sorry it took so long to get an answer</span>
Answer:
3.76
Explanation:
We are given that
Terminal speed in the spread -eagle position,
Terminal speed in the nosedive position,
We have to find the ratio of the effective cross-sectional area A in the slower position to that in the faster position.
We know that
Area, A=
False because the more mass and object has, the more force you will need to move that object.
