Given :
Center of sphere , C( 1 , -1 , 6 ) .
To Find :
Find equations of the spheres with center (1, −1, 6) that touch the following planes.a) xy-plane b) yz-plane c) xz-plane .
Solution :
a)
Distance of the point from xy-plane is :
d = 6 units .
So , equation of circle with center C and radius 6 units is :
b)
Distance of point from yz-plane is :
d = 1 unit .
So , equation of circle with center C and radius 1 units is :
c)
Distance of point from xz-plane is :
d = 1 unit .
So , equation of circle with center C and radius 1 units is :
Hence , this is the required solution .
4 2/11 = 4.1818181
sqrt5 = 2.2360679......
3/16 = 0.1875
answer:
3/16 terminates ( it only has 4 numbers)
4 2/11 don't terminate but keeps repeating
sqrt5 doesn't terminate or repeat
Answer:
(1,0)
Step-by-step explanation:
This is because a system of equations is when two lines cross to form a point that they share. (1,0) is the point where the two lines cross/intersect.
Answer:
Step-by-step explanation:
H = V/ pie r^2
H = 
R= 5 because the radius is half the diameter
Pies cancel out leaving you with:
H = 2200/5^2
H = 2200/25
H = 88
Hope this helps :)
Answer:
Step-by-step explanation:
Factor the sum of cubes
a³ + b³ = (a+b)(a² - ab +b²)
= 2a² - 2ab + 2b²
a³ + b³ + 6ab = 2a² + 4ab + 2b²
= 2(a² + 2ab +b²)
= 2(a+b)²
= 8
