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guapka [62]
3 years ago
13

1. Given rhombus RSTV, where the perimeter is 20cm and the area is 25cm². If rhombus RSTV is dilated by a scale factor of 3 abou

t a given center. a) What is the perimeter, in centimeters, of the image of RSTV after the dilation? b) What is the area, in centimeter squares, of the image RSTV after the dilation? 2) Given rectangle ABCD where the perimeter is 12cm and the area is 36cm². If rectangle RSTV is dilated by a scale factor of 4 about a given center. a) What is the perimeter, in centimeters, of the image of RSTV after the dilation? b) What is the area, in centimeter squares, of the image RSTV after the dilation.
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
6 0

Answer:

The answer is A

Step-by-step explanation:

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It cost 17 and $.70 send 170 in text messages how many text messages did you send if you spent $19.10?
ZanzabumX [31]

Answer:

184

Step-by-step explanation:

17.70 / 170 = .104 per text

19.10 / .104 = 183.65 round up to 184

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Please help!!! My math teacher doesn’t explain things well.
abruzzese [7]

When you look at the graph, the X is the x value and the one on the f(x) is the y value, imagian it is on a graph and x is the steps you have to walk then imagain a ladder you have to go as high as the f(x) value says, then mark them. if they follow a pattern then write it down, if it does not then write incosentant.

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3 years ago
Please help me?<br><br> please and thanks
AVprozaik [17]

Answer:

-\frac{35}{2}

Step-by-step explanation:

-5 ÷ \frac{2}{7} = 17\frac{1}{2}

17\frac{1}{2} = -\frac{35}{2}

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3 years ago
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2 years ago
When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for
juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where n= sample size

\hat{p} = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = \hat{p}=\dfrac{106}{258}\approx0.411

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the  99% confidence interval for the true proportion(p) of all college students who own a car will be :0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490

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3 years ago
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