Answer:
B.) The graph of m(x) is wider.
Both graphs open upward.
Both have the axis of symmetry x = 0.
The vertex of m(x) is (0, 4); the vertex of n(x) is (0, 0).
Step-by-step explanation:
When the coefficient before x² is greater than 1, the curve of the graph is narrower. When the coefficient is less than 1, the curve of the graph is wider.
When the coefficient in front of x² is positive, the graph opens upwards. When the coefficient is negative, the graph opens downwards.
The axis of symmetry is the "x" value which divides the curve into two equal sections. Their axis of symmetry are both x = 0 because their vertexes (the lowest point of the curve) are both at x = 0.
The vertex can be found by plugging x = 0 into both of the equations and then solving. The resulting value is the "y" position of the vertex.
m(0) = 0.7(0)² + 4 n(0) = (0)²
m(0) = 0 + 4 n(0) = 0
m(0) = 4
Therefore, the vertexes are m(x) = (0,4) and n(x) = (0,0).
((6*2)+y)+(x+15)
i hope this helps if not sorry
Answer:
A proportional relationship is something like:
y = k*x
Where k is the constant of proportionality
And a linear relationship is something like:
y = a*x + b
Is easy to see that if:
a = k, and b = 0, this would be a proportional relationship.
Then if we want to have a slope equal to 3, but this must not be a proportional relationship, we must only have b different than 0.
This could be something like:
y = 3*x + 1
The graph of this is:
