Answer: Option D. 1,778
Solution:
Standard brick:
Width: w=3.625 in
Height: h=2.25 in
Length: l=7.625 in
Volumen of one standard brick: v
v=w*h*l
v=(3.625 in)*(2.25 in)*(7.625 in)
v=62.19140625 in^3
Pallet of bricks:
Side: s=4 feet
s=(4 feet)*(12 in / 1 feet)→s=48 in
Volume of a pallet of bricks: V=s^3
V=(48 in)^3
V=110,592 in^3
Number of bricks could be in a pallet: n
n=V/v
n=(110,592 in^3) / (62.19140625 in^3)
n=1,778.252119
n=1,778
Answer:
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Answer:
- The graph has an open circle at 7.
- The arrow points left.
Step-by-step explanation:
Adding 10 and dividing by 4, we have ...
4x < 28
x < 7
The comparison does not include the "equal to" case, so the circle at x=7 is open. Values of x less than 7 are in the solution set. Those values are found to the left of 7 on the number line.
- The graph has an open circle at 7.
- The arrow points left.
Answer:
-18 and 2
Step-by-step explanation:
- 18 x 2 = -36
-18 + 2 = -16