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3 years ago

HELP PLZZZZZZZZZZ I WILL GIVE BRAINLIEST

Mathematics

1 answer:

klasskru [66]3 years ago

6 0

The answer is A since you just plug in -2for all the x’s

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Pls help me frens......

Natalija [7]

Answer:

V= 8

x=4.5

BCF =48 CFE=132

V=352.8 =8.4x8.4x5

For the volume one i cant read the number but if the bottom number is 8 then V=803.84

if its 6 then v = 452.16

Step-by-step explanation:

v= 2x2x2 v = 8

x is 11x-9=7x+9 | 4x=18 | x=4.5

15x=180 x=12 | CFE = 11x12=132 | BCF = 4x12=48

4 0

3 years ago

What percentage of 48 is 62?

Mila [183]

Answer:

129

Step-by-step explanation:

6 0

2 years ago

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If Georgina travels 455 km in 7 hours how far will she travel in 9 hours at the same rate

11111nata11111 [884]

585:)) 455\7=65 65•9=585

4 0

3 years ago

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If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .