Answer:
x = ± 2i
Step-by-step explanation:
note that 
= i
x² = - 12 ( take square root of both sides )
x = ± 
= ± 
= ± 2i
A= P(1 + r) n (n to the power of)
<span>A= final balance </span>
<span>P= initial quantity </span>
<span>n= number of compounding periods </span>
<span>r= percentage interest rate </span>
<span>P= $200 </span>
<span>n= 9 years </span>
<span>r= 5%= 0.05 </span>
<span>=$200 (1 + 0.05)9 (power of) </span>
<span>=$310.26</span>
-45+18x is the answer
Hope this helped <3
The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
Given that,
The function is (-x+3)/ (3x-2)
We have to find f(1) and f'(x).
Take the function expression
f(x)= (-x+3)/ (3x-2)
Taking x as 1 value
f(1)= (-1+3)/(3(1)-2)
f(1)=2/1
f(1)=1
Now, to get f'(x)
With regard to x, we must differentiate.
f(x) is in u/v
We know
u/v=(vu'-uv')/ v² (formula)
f'(x)= ((3x-2)(-1)- (-x+3)(3))/ (3x-2)²
f'(x)= ((-3x+2)-(-3x+9))/ 9x²- 12x+4
f'(x)=(-3x+2+3x-9)/ 9x²- 12x+4
f'(x)=2-9/ (9x²- 12x+4)
f'(x)=-7/ (9x²- 12x+4)
Therefore, The function is (-x+3)/ (3x-2) and we get f(1)=1 and differentiation is f'(x)=-7/ (9x²- 12x+4).
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