The answer is B) 8.
There are 5 genes. There are two possibilities for each of the heterozygous genes and only one possibility for each of homozygous genes. So, the possibilities for each gene are:
Aa - 2: A or a;
Bb - 2: B or b;
CC - 1: D;
Dd - 2: D or d;
EE - 1: E.
Genotype AaBbCCDdEE will have
2 x 2 x 1 x 2 x 1 gametes
Thus, there will be 8 unique gametes produced by an <span>individual with the genotype AaBbCCDdEE</span>
Answer:
radial brusa and ulnar brusa
Explanation:
median nerve
Answer: All their offsprings will be heterozygous for both traits.
Explanation: The offsprings of this cross will be heterozygous for the two traits. Each the offspring will have one dominant allele and one recessive allele for both traits. All the offsprings will have a genotype of BbEe. B is a dominant allele and b is a recessive allele while E is a dominant allele and b is a recessive allele.
The answer is her daughter or son, as this is the first person who is responsible of taking care of her when she no longer can take care of herself and when she does not have any place to go because the family is one of the people who will be responsible of looking out of each members in the family.
