Answer:
Do you want to be extremely boring?
Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?
is a valid solution.
Want something more fun? Why not a parabola?
.
At this point you have three parameters to play with, and from the fact that
we can already fix one of them, in particular
. At this point I would recommend picking an easy value for one of the two, let's say
(or even
, it will just flip everything upside down) and find out b accordingly:
Our function becomes
Notice that it works even by switching sign in the first two terms: 
Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: 
Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need
, and at that point the first condition is guaranteed; using the second to find k we get 

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

Sky is the limit.
Answer:
10, and 4.
Step-by-step explanation:
39+48=87
87-13=74
74 divided by 7= 10 R4
Greatest amount of bricks= 10
Leftovers= 4.
I apologize, but we would need the chart included below the questions to be able to answer this.
Answer:
b = infinity
Step-by-step explanation:
1 − 3(3 + 6b) = −6(3b + 1) − 2
1 - 9 - 18b = -18b + 1 -2
1 - 9 = 1 - 2
-8 = -1
399,713 rounded to the nearest thousand is 400,000