All categories

3 years ago

2x - 6y = 12 2x – 4y = 8

Mathematics

1 answer:

Alenkasestr [34]3 years ago

7 0

Answer:

true

Step-by-step explanation:

You might be interested in

When a spherical balloon is filled with air, it has a radius of 3 inches. Which of these gives the best estimate for the volume

marysya [2.9K]

By definition, the volume of a sphere is given by:
V = (4/3) * (pi) * (r ^ 3)
where,
r: radius of the sphere.
Substituting we have:
V = (4/3) * (pi) * ((3) ^ 3) = 113.08 in ^ 3
answer
the best estimate for the volume of air in the balloon in cubic inches is
C. 113.1

3 0

3 years ago

Read 2 more answers

Simplify 3a + 2b - 8a + b

Harlamova29_29 [7]

To simplify 3a + 2b - 8a + b, we need to combine like terms. Like terms are terms that share common variables. In this expression, the two variables are terms with a and terms with b. The terms that have a are 3a and -8a. The terms that have b are 2b and b. Now we can separate them and simplify.

(3a - 8a) + (2b + b)

-5a + 3b

6 0

3 years ago

Read 2 more answers

Solve the system of equations algebraically.

ryzh [129]

Answer:

Step-by-step explanation:

y=3x+24

y-3x=24

y-x= 24/3= 8

y-x = 8

6x +6y= -24

6x+y= -24/6= -4

6x+y= -4

x+y= -4/6= -2/3

x+y= -2/3

8 0

1 year ago

Read 2 more answers

An experiment consists of drawing 1 card from a standard 52-card deck. what is the probability of drawing a diamond

tankabanditka [31]

There are 13 diamonds in a deck of cards, so the chances of drawing a diamond is 1/4

8 0

3 years ago

Tags are attached to the left and right hind legs of a cow in a pasture. Let A1 be the event that the left tag is lost and the e

ioda

Answer:

Step-by-step explanation:

Given that tags are attached to the left and right hind legs of a cow in a pasture. Let A1 be the event that the left tag is lost and the event that the right leg tag is lost. Suppose those two events are independent and A2 the event that the right leg tag is lost. Suppose those two events are independent and P(A1) = P(A2) = 0.3

a) the probability that at least one leg tag is lost

= $P(A_1 U A_2)\\= P(A_1) + P(A_2)-{(A_1 \bigcap A_2)\\=P(A_1) + P(A_2)-{(A_1 )P(A_2)$

(since A1 and A2 are independent)

=0.3+0.3-0.09

=0.51

b) the probability that exactly one tag is lost, given that at least one tag is lost.

= P(one leg lost)/P(atleast one leg lost)

= $P(atleast one leg lost)-P(Both lost)/0.51\\= \frac{0.51-0.09}{0.51} \\=14/17$

c) the probability that exactly one tag is lost, given that at most one tag is lost.

4 0

3 years ago