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3 years ago

6. Consider a circle of diameter d cm.

Computers and Technology

1 answer:

blagie [28]3 years ago

8 0

Circles

Area of Circle is $\pi d^{2} /4$

Total percentage increase in the area of the modified circle is 69%

Explanation:

(a) Given the diameter of the circle be d

Then the radius of the circle = r = d/2

and the area of the circle is given by:

Area(A) = $\pi r^{2}$

A = $\pi (d/2)^{2}$

A = $\pi d^{2} /4$

The area of circle is $\pi d^{2} /4$

(b)

The increase in percentage while changing the dimensions is given by the formula :

Total % increase = a% + b% - (a% * b%)/100

Where ,

a% is the percentage increase in side a

b% is the percentage increase in side b

Let the percentage increase in radius is : a%

Since a% = b%

So the formula is

Total increase % = a% + a% + (a% * a%)/100

Given here the diameter of the circle increases by 30% so a =30

Therefore, putting the value of a in the formula

Total increase % = 30% + 30% + (30% *30%)/100

Total increase % = 60% + 9%

Total increase % =69%

Therefore the total percentage increase in the area of the modified circle is 69%

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public class Digits

{

public static boolean allDigitsOdd(int num)

{

boolean flag=true;

int rem;

while(num>0)

{

rem=num%10;

num=num/10;

if(rem%2==0) // if a even digit found immediately breaks out of loop

{

flag=false;

break;

}

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public static void main(String args[])

{

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}

OUTPUT :

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