Answer and Explanation:
Using javascript:
function dayof_theweek(){
var TodayDate = window. prompt("enter today's date in the format 'year, month, day' ");
var Datenow=new date(TodayDate);
var Dayofweek=Datenow.getday();
var Days=["monday","Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"];
if(Dayofweek==indexOf(Days[Dayofweek]))
{
document.createTextnode(Days[Dayofweek]);
}
}
The program above uses a date object which uses the method getday to get the day of the week(get day returns an integer from 0 to 6).we then use a comparison operator == to test the condition that returned value Dayoftheweek is same with the index of the array Days and then print to a html document. The program may need improvements such as the fact that errors may arise when proper input isn't given, and therefore must be handled.
The answer is HTTP protocol
Answer:
A . if you burn a stump because if u roll over the fire will have a 90% chance of going out
Answer:
C. Access mask discretionary.
Explanation:
Access_Mask is the value that defines the rights used in access control entries (ACE), this value identifies if the trustee is allowed to access a secured object.
It can define rights in three categories: Standard, specific and generic rights.
def GPAcalc(grade, weighted):
grade = grade.lower()
dictionary = {"a": 4, "b": 3, "c": 2, "d": 1, "f": 0}
if weighted == 1 and grade in dictionary:
return "Your GPA score is: "+str(dictionary[grade] + 1)
elif weighted == 0 and grade in dictionary:
return "Your GPA score is : "+str(dictionary[grade])
else:
return "Invalid"
print(GPAcalc(input("Input a letter grade: "), int(input("Is it weigthed? (1= yes, 0= no)"))))
I modified the code a bit to cut down on the use of if and elif statements. If you need me to change it, I will. Best of luck.
