I need serious help. Please
2 answers:
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Answer:
- x = ±√3, and they are actual solutions
- x = 3, but it is an extraneous solution
Step-by-step explanation:
The method often recommended for solving an equation of this sort is to multiply by the product of the denominators, then solve the resulting polynomial equation. When you do that, you get ...
... x^2(6x -18) = (2x -6)(9)
... 6x^2(x -3) -18(x -3) = 0
...6(x -3)(x^2 -3) = 0
... x = 3, x = ±√3
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Alternatively, you can subtract the right side of the equation and collect terms to get ...
... x^2/(2(x -3)) - 9/(6(x -3)) = 0
... (1/2)(x^2 -3)/(x -3) = 0
Here, the solution will be values of x that make the numerator zero:
... x = ±√3
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So, the actual solutions are x = ±3, and x = 3 is an extraneous solution. The value x=3 is actually excluded from the domain of the original equation, because the equation is undefined at that point.
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<em>Comment on the graph</em>
For the graph, we have rewritten the equation so it is of the form f(x)=0. The graphing program is able to highlight zero crossings, so this is a convenient form. When the equation is multiplied as described above, the resulting cubic has an extra zero-crossing at x=3 (blue curve). This is the extraneous solution.
The surface area of a cylinder is the area of the bases plus the area of the side, or SA = 2*A₁ + A₂
Since the area of a circle is
,
SA = 2*() + A₂
Since the area of the side is height * the circumference of the circle or A₂ = h *
, then SA must be;
SA =
SA =
SA =
SA ≈ <span>351.858377202</span>
Since the area of a circle is
SA = 2*(
Since the area of the side is height * the circumference of the circle or A₂ = h *
SA =
SA =
SA =
SA ≈ <span>351.858377202</span>