Question

What is the height of this isosceles triangle?

Answer 1

Answer:

height ≈ 11.9 units

Step-by-step explanation:

Construct a perpendicular bisector from the vertex to the base, thus splitting the triangle into 2 right triangles.

Using the sine ratio in one of these right triangles, then

sin48° = $\frac{opposite}{hypotenuse}$ ( the opposite is the height h )

sin48° = $\frac{h}{16}$ ( multiply both sides by 16 )

16 × sin48° = h , thus

h ≈ 11.9 ( to the nearest tenth )