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blagie [28]
3 years ago
10

What is the height of this isosceles triangle?

Mathematics
1 answer:
erastova [34]3 years ago
5 0

Answer:

height ≈ 11.9 units

Step-by-step explanation:

Construct a perpendicular bisector from the vertex to the base, thus splitting the triangle into 2 right triangles.

Using the sine ratio in one of these right triangles, then

sin48° = \frac{opposite}{hypotenuse} ( the opposite is the height h )

sin48° = \frac{h}{16} ( multiply both sides by 16 )

16 × sin48° = h , thus

h ≈ 11.9 ( to the nearest tenth )

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Answer: 44

Step-by-step explanation:

we will find RN and NQ, then add together to give us RQ.

To find RN;

RP= 17 PN = 15 and RN =?

using pythagoras theorem,

adj^2 = hyp^2 - opp^2

RN^2 = RP^2 - PN^2

?^2 = 17^2 - 15^2

?^2 = 17^2 - 15^2

?^2 = 289 - 225

?^2 = 64

? = √64

? = 8

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To find NQ,

PN = 15 PQ=39 and NQ=?

using pythagoras theorem

NQ^2 = PQ^2 - PN^2

?^2 = 39^2 - 15^2

?^2 = 1521 - 225

?^2 = 1296

? = √1296

? = 36

NQ= 36

RQ = RN + NQ

RQ= 8 + 36

RQ=44

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