What is the height of this isosceles triangle?
1 answer:
Answer:
height ≈ 11.9 units
Step-by-step explanation:
Construct a perpendicular bisector from the vertex to the base, thus splitting the triangle into 2 right triangles.
Using the sine ratio in one of these right triangles, then
sin48° = ( the opposite is the height h )
sin48° = ( multiply both sides by 16 )
16 × sin48° = h , thus
h ≈ 11.9 ( to the nearest tenth )
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Step-by-step explanation:
Hey, there!!!
Let me simply explain you about it.
We generally use the distance formula to get the points.
let the point R be (x,y)
As it an equilateral triangle it must have equal distance.
now,
let's find the distance of PQ,
we have, distance formulae is;
By simplifying it we get,
Now,
again finding the distance between PR,
or,
By simplifying it we get,
now, finding the distance of QR,
or, by simplification we get,
now, equating PR and QR,
we cancelled the root ,
or, cancelling all like terms, we get,
6x+13= -10x+29
16x=16
x=16/16
Therefore, x= 1.
now,
equating, PR and PQ,
cancel the roots,
now,
(1)^2+ y^2+6×1-4y+13=8
or, 1+y^2+6-4y+13=8
y^2-4y+13+6+1=8
or, y(y-4)+20=8
or, y(y-4)= -12
either, or,
y= -12 y=8
Therefore, y= (8,-12)
by rounding off both values, we get,
x= 1
y=(8,-12)
So, i think it's (1,8) is your answer..
<em>Hope it helps</em><em>.</em><em>.</em><em>.</em>