I don't know what you mean but when you want to find equivalent fractions, I would use 10.
Ex: 6/9=60/90
Answer:9.7536Step-by-step explanation:
All work<span> should be submitted in its original form. ... (b) </span>If<span> v=— </span>show<span> that z=a^~^\ and </span>find<span> from either equation 1 ' " x-a' p—a' H the </span>value<span> of a in order that </span>x<span>='i when y=2. Also, for this ... Thence </span>find<span> the length of an edge of such a box weighing </span>18<span>$ pounds, </span>if<span> the thickness is 1 inch and the weight 1 ounce to the cubic inch.</span>
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
The correct answer is:
(a) 0.54
(b) 0.0385
Step-by-step explanation:
Given:
Restaurant tax,
p = 0.54
Sample size,
n = 168
Now,
(a)
The mean will be:
⇒ μ 

(b)
The standard error will be:
= ![\sqrt{[\frac{p(1-p)}{n} ]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%20%5D%7D)
= ![\sqrt{[\frac{(0.54\times 0.46)}{168} ]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%5Cfrac%7B%280.54%5Ctimes%200.46%29%7D%7B168%7D%20%5D%7D)
= ![\sqrt{[\frac{(0.2484)}{168} ]}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%5Cfrac%7B%280.2484%29%7D%7B168%7D%20%5D%7D)
= 