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Natali [406]
3 years ago
10

Intergrate x×(x²-3)³

Mathematics
1 answer:
Kisachek [45]3 years ago
4 0

Answer:   \large \boldsymbol{\dfrac{1}{8 } (x^2-3)^4+c}

Step-by-step explanation:

\displaystyle \large \boldsymbol{}  \int\limits {x(x^2-3)^2 } \, dx =\int\limits \frac{1}{2}  {} \, (x^2-3)' (x^2-3)^3 dx  =\frac{1}{8}  (x^2-3)^4+c

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