Question

Intergrate x×(x²-3)³

Answer 1

Answer:   $\large \boldsymbol{\dfrac{1}{8 } (x^2-3)^4+c}$

Step-by-step explanation:

$\displaystyle \large \boldsymbol{} \int\limits {x(x^2-3)^2 } \, dx =\int\limits \frac{1}{2} {} \, (x^2-3)' (x^2-3)^3 dx =\frac{1}{8} (x^2-3)^4+c$