Intergrate x×(x²-3)³

Mathematics

1 answer:

Kisachek [45]3 years ago

4 0

Answer: $\large \boldsymbol{\dfrac{1}{8 } (x^2-3)^4+c}$

Step-by-step explanation:

$\displaystyle \large \boldsymbol{} \int\limits {x(x^2-3)^2 } \, dx =\int\limits \frac{1}{2} {} \, (x^2-3)' (x^2-3)^3 dx =\frac{1}{8} (x^2-3)^4+c$

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Answer:

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Step-by-step explanation:

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never [62]

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