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Illusion [34]
2 years ago
14

Find the area of the trapezoid. b1=5 b2=7 h=4 PLEASE EXPLAIN TOO!

Mathematics
2 answers:
olga_2 [115]2 years ago
4 0

Step-by-step explanation:

The formula for finding the area of a trapezoid is\frac{b_{1} + b_{2} }{2} ×h

Start by substituting the values given in the problem into the formula

\frac{5+7}{2} ×4

Now Simply/solve

\frac{12}{2} ×4

6×4

24

The area of the trapezoid is 24units^{2}

I hope this helps!!!

Evgen [1.6K]2 years ago
4 0

Answer: The answer is 6.

Step-by-step explanation: Solve the indicated variable. Multiply both sides by 2 . Divide both sides  by h

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Solve each problem by working backward.
OLEGan [10]

Answer: X= 4/3 I hope this helps:)

Step-by-step explanation:

(3x ). • 4= 16

divide by 4

3x = 4

divide by 3

x= 4/3

3 0
3 years ago
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What percent of 60 is 12? Show your work. Is this wrong or right. 60/100 = 0.6*12 7.2% or do i removes the .2 off the percentage
Troyanec [42]
You don't just go removing numbers here and there without a good reason. In any case, your whole approach here is wrong. You're calculating 60 percent of 12. But the question says to take 12 out of a group of 60 and tell what percent of the group you have. That's (12/60) x 100.
5 0
3 years ago
PLZ, help me with this question.
Korolek [52]

Answer:

Intensity

Step-by-step explanation:

In physics, intensity of radiant energy is the power transferred per unit area, where the area is measured on the plane perpendicular to the direction of propagation of the energy.

8 0
3 years ago
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A triangle PQR is right angled at R, with PQ=80cm and R=60cm. find QR?<br> pythagorus theorem
algol13

Answer:

Solution given:

A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm

and

base[b]PR=60cm.

perpendicular [P]= QR

<u>by</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>

<u>h²</u><u>=</u><u>p²</u><u>+</u><u>b²</u>

80²=QR²+60²

QR²=80²-60²

QR=\sqrt{2800}

QR=20\sqrt{7}=52.9=53cm

<u>QR</u><u>=</u><u>5</u><u>3</u><u>c</u><u>m</u><u>.</u>

5 0
3 years ago
Find the sum of the arithmetic sequence. 5,7,9,11,...,23
eduard

Answer:

140

Step-by-step explanation:

The arithmetic series is 5, 7, 9, 11, ........., 23.

First u have to determine the no. of terms that can be done by using

Tₙ = [a + (n - 1)d]

Tₙ-------nth term

a---------first term

n---------no.of terms in the series

d---------common difference

here a = 5,d = 2.

let it contain n terms Tₙ= [a + (n-1)d]

Substitute Tₙ, a, and d in the equation

23 = 5 + (n - 1)2

Subtract 5 from each side.

18 = (n-1)2

Divide each side by 2

(n - 1) = 9

Add 1 to each side

n = 9 + 1 = 10

The sum of the arithmetic sequence formula: Sₙ= (n/2)[2a+(n-1)d]

Substitute Sₙ, a, n and d in the equation

Sₙ= (10/2)[2(5) + (10-1)2]

Sₙ= (5)[10 + (9)2]

Sₙ= 5[10 + 18]

Sₙ= 5[28] = 140

Therefore the sum of the arithmetic sequence is 140.

6 0
2 years ago
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