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xeze [42]
3 years ago
7

Find the sum. 1/4 + 2/7 a. 9/14 b. 3/11 c. 15/28 d. 3/28

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0
1/4 + 2/7 =

The denominators 4 and 7 lcm are 28

So,
1/28 + 2/28 = 3/28

3/28 is the answer to your question.
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Identify the horizontal asymptote of f(x) = quantity 2 x minus 1 over quantity x squared minus 7 x plus 3.
Rina8888 [55]
We must recall that a horizontal asymptote is the value/s of y that the given function approaches to but never reaches. To find this in a rational function, we compare the expressions with highest degree in the numerator and denominator. There are three possible outcome when this happens.

1. if the highest degree (highest exponent) in the numerator is bigger than that of the denominator, then there won't be any horizontal asymptote.

2. if the highest degree in the denominator is bigger, then the horizontal symptote would be y = 0.

3. if they have the same highest degree, then we just get the quotient of their coefficient. 

Now, going back to our function, we have

f(x) = \frac{2x - 1}{x^{2} - 7x + 3}

From this we can see that the highest degree in the numerator is 1 (from 2x) and 2 (from x²) for the denominator. Clearly, it shows that its denominator has a higher degree. And from our discussion, we can conclude that the horizontal asymptote would be y = 0.

Answer: y = 0
3 0
3 years ago
Berry waked the dog for 20 minutes.
Sergeu [11.5K]
Chris walked the dog for 80 minutes or 1 hour and 20 minutes
5 0
3 years ago
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Find the perimeter of a regular octagon if one side has a measure of 8cm A) 16 cm B) 56cm C) 64cm D) 72cm
zysi [14]
C. 64cm 
Hope this helps! :)
8 0
3 years ago
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The measure of an angle is 133°. What is the measure of its supplementary angle?
Pachacha [2.7K]

Answer:

47

Step-by-step explanation:

180 - 133 = 47

7 0
3 years ago
Rewrite by completing the square 2x^2+7x+6=0
Kitty [74]

Answer:

2x^2+7x+6=0\\\\2(x^2+\frac72x+3)=0\\\\2[x^2+2\cdot x\cdot\frac74+(\frac74)^2-(\frac74)^2+3]=0\\\\2[x^2+2\cdot x\cdot\frac74+(\frac74)^2]-2(\frac74)^2+6=0 \\\\2(x+\frac74)^2-2\cdot\frac{49}{16}+6=0\\\\2(x+\frac74)^2-\frac{49}8+\frac{48}8=0\\\\2(x+\frac74)^2-\frac18=0

6 0
3 years ago
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