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xeze [42]
3 years ago
7

Find the sum. 1/4 + 2/7 a. 9/14 b. 3/11 c. 15/28 d. 3/28

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0
1/4 + 2/7 =

The denominators 4 and 7 lcm are 28

So,
1/28 + 2/28 = 3/28

3/28 is the answer to your question.
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A ______ is a graph of data based on quartiles showing a rectangle with lines extending from both its ends.
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<h3>Answer: boxplot</h3>

Another alternative answer is "box-and-whisker plot"

The box portion consists of data between Q1 and Q3, with the median somewhere in between. The whiskers represent stuff below Q1 and above Q3. The tip of each whisker represents the min and max, assuming there are no outliers. If there are outliers, then you'll have island points disconnected from the main boxplot.

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A car speed up from 10 mph to 50 mph over a time<br> period of 10 seconds What is the acceleration?
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3 years ago
Which of the following represents the general term for the sequence 1, 3, 5, 7, 9, . . .? n
zalisa [80]

Answer:

Step-by-step explanation:

In the given sequence, the terms are increasing in arithmetic progression. The common difference, d between successive terms is 2

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Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 1

d = 2

Therefore, the expression for the general term for the sequence is

Tn = 1 + 2(n - 1)

3 0
3 years ago
Pablo graphs a system of equations. One equation is quadratic and the other equation is linear. What is the greatest number of p
Nady [450]
For this case we have the following type of equations:
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 y = mx + b&#10;
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 ax ^ 2 + bx + c = mx + b&#10;
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7 0
3 years ago
Read 2 more answers
第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows
tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

P(A/B)=\frac{P(A)*P(B/A)}{P(B)}

let A be the  event that the student knows the answer .

B be  the  event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}

Probability that the answer is correct ,given that he knows the answer is

P(E/A)=1

Probability that the answer is correct ,given that he guesses it is

P(E/B)=\frac{1}{3}   [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}

Substituting the values we get

P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }

=\frac{6}{30}*\frac{30}{18}  \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}

Therefore ,  the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

#SPJ4

8 0
11 months ago
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