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3 years ago

Is 6,500 ten times as much as 65 explanation and how to get the answer

Mathematics

1 answer:

stellarik [79]3 years ago

5 0

No, 6,500 is one hundred times as much as 65, because of the two zeros on the end. 100 and 6,500.

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If (3). write the following vectors in column vector form:

Art [367]

Answer:

see explanation

Step-by-step explanation:

Given

a = $\left[\begin{array}{ccc}3\\2\\\end{array}\right]$

To obtain -3a multiply each of the elements of a by -3

3a = $\left[\begin{array}{ccc}-3(3)\\-3(2)\\\end{array}\right]$ = $\left[\begin{array}{ccc}-9\\-6\\\end{array}\right]$

To obtain 1.5a multiply each element by 1.5

1.5a = $\left[\begin{array}{ccc}1.5(3)\\1.5(2)\\\end{array}\right]$ = $\left[\begin{array}{ccc}4.5\\3\\\end{array}\right]$

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3 years ago

HELPPP ILL DO ANYTHING HELPPPP

katovenus [111]

Answer:

-2

Step-by-step explanation:

hi! to find f(-3) on this graph, go to the x-value -3 and find the y-value there. when we look at -3 on the x-axis, we go down and see that there is a point at (-3,-2). therefore, f(-3)=-2.

3 0

3 years ago

Which pair of lines are parallel? Need to show work

zaharov [31]

Answer:

Step-by-step explanation:

7 0

3 years ago

The total length of pencils A, B and C is 29 cm. Pencil a is 11 cm shorter then pencil B, and pencil B is twice as long a pencil

satela [25.4K]

The length of pencil A is 5 cm

Solution:

Let the length of pencil A be "x"

Let the length of pencil B be "y"

Let the length of pencil C be "z"

The total length of pencils A, B and C is 29 cm

Therefore,

length of pencil A + length of pencil B + length of pencil C = 29

x + y + z = 29 ------------ eqn 1

Pencil A is 11 cm shorter then pencil B

x = y - 11 ------- eqn 2

Pencil B is twice as long a pencil C

y = 2z

$z = \frac{y}{2}$ ------ eqn 3

Substitute eqn 2 and eqn 3 in eqn 1

$y - 11 + y + \frac{y}{2} = 29\\\\2y + \frac{y}{2} = 29 + 11\\\\\frac{4y+y}{2} = 40\\\\5y = 80\\\\y = 16$

Substitute y = 16 in eqn 2

x = 16 - 11

x = 5

Thus length of pencil A is 5 cm

5 0

3 years ago

Is there enough information?

Minchanka [31]

Yea and the theorem is SAS

3 0

3 years ago