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nydimaria [60]
3 years ago
8

On-the-Go Phone Company has two monthly plans for their customers.The EZ Pay Plan costs $0.15 per minute. The 40 to Go Plan cost

s $40 per month plus $0.05 per minute. Write an expression that represents the monthly bill for x minutes on EZ Pay Plan.
Mathematics
2 answers:
natulia [17]3 years ago
4 0
For one moth it would be....
30 + 40 + 0.05
$57.00 In total but im not sure if this is correct so if you could make sure please.
alexandr1967 [171]3 years ago
4 0

Answer: Expression that represents the monthly bill for x minutes on EZ pay plan is 0.15x

Step-by-step explanation:

Since we have given that

Cost per minute through EZ Pay plan = $0.15

Cost of Go plan per month = $30

Cost per minute in Go plan = $0.05

so, Expression for EZ pay plan is given by

0.15x

Expression for Go plan is given by

40+0.05x

Hence, expression that represents the monthly bill for x minutes on EZ pay plan is 0.15x

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A pool is being drained at a rate of 120 gallons per minute.What is this rate in quarts per hour?
zysi [14]
There are 4 quarts in 1 gallon, so a rate of 120 gallons per minute converts to 4 x 120 = 480 quarts per minute. To find the per hour rate, we simply multiply our per minute rate by 60, obtaining 480 x 60 = 28800 quarts per hour.
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How much money does the average professional hockey fan spend on food at a single hockey​ game? That question was posed to 10 ra
Vinil7 [7]

Answer:

Now we have everything in order to replace into formula (1):

18-2.262\frac{2.75}{\sqrt{10}}=16.03    

18+2.262\frac{2.75}{\sqrt{10}}=19.97    

Step-by-step explanation:

Information given

\bar X=18 represent the sample mean

\mu population mean (variable of interest)

s=2.75 represent the sample standard deviation

n=10 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=10-1=9

The Confidence is 0.90 or 90%, the significance is \alpha=0.1 and \alpha/2 =0.05, and the critical vaue would be t_{\alpha/2}=2.262

Now we have everything in order to replace into formula (1):

18-2.262\frac{2.75}{\sqrt{10}}=16.03    

18+2.262\frac{2.75}{\sqrt{10}}=19.97    

5 0
2 years ago
PLEASE CAN SOMEONE HELP!!!!!!!!!!!!!!!!<br><br> How can you use subtraction to describe division?
STatiana [176]
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5 0
3 years ago
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Which function is defined for x=0
Sav [38]

0 would be on the top, hope this helps

4 0
3 years ago
Lucy is using a one-sample t ‑test based on a simple random sample of size n = 22 to test the null hypothesis H 0 : μ = 16.000 c
slega [8]

Answer:

The value of test statistic is 1.338

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 16.000

Sample mean, \bar{x} = 16.218

Sample size, n = 22

Alpha, α = 0.05

Sample standard deviation, s = 0.764

First, we design the null and the alternate hypothesis

H_{0}: \mu = 16.000\text{ cm}\\H_A: \mu < 16.000\text{ cm}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{16.218 - 16.000}{\frac{0.764}{\sqrt{22}} } = 1.338

Thus, the value of test statistic is 1.338

4 0
3 years ago
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