The correct answer is the One fired from from 60° . This is because the projectile fired from 60° has a greater vertical velocity compared to the one fired from 30° and therefore spends more time on air. Vertical velocity is the velocity of a body as it moves upwards, it is normally affected by the gravitational acceleration, however it is not affected by the horizontal velocity.
Answer:
The answer is five!
Step-by-step explanation:
Always read down then up!
Answer:
y = 5/7x - 6 the slip should be positive and do the rise over run using 5/7 and make it go through -6 as the y and 1 add the x
Answer: (x - 2y) + 3
Step-by-step explanation: The quantity x minus 2y is (x - 2y), then we add 3.
![\dfrac{\mathrm d}{\mathrm dt}\left[2x^2+y^3\right]=\dfrac{\mathrm d}{\mathrm dt}[10]\implies 4x\dfrac{\mathrm dx}{\mathrm dt}+3y^2\dfrac{\mathrm dy}{\mathrm dt}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5B2x%5E2%2By%5E3%5Cright%5D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5B10%5D%5Cimplies%204x%5Cdfrac%7B%5Cmathrm%20dx%7D%7B%5Cmathrm%20dt%7D%2B3y%5E2%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dt%7D%3D0)
When

, the original equation tells you that you have

You also know that when

, you have

. Substituting everything you know into the differentiated equation, you get

So

is changing at a rate of

.