c. Find the equation of a straight line which passes through the point (4,4) and whose intercept on the x-axis is 5 times its in
1 answer:
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Answer:
y = -2/5x +36/5 . . . . . slope-intercept form
2x +5y = 36 . . . . . . . . standard form
Step-by-step explanation:
You can use the 2-point form of the equation of a line to find it.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
y = (4 -6)/(8 -3)(x -3) +6
y = -2/5(x -3) +6
y = -2/5x +36/5 . . . . slope-intercept form
2x +5y = 36 . . . . . . . standard form
You are looking for the shaded region that would be contained in both of the inequalities.
You have:
If you graph an shade the correct half-plane for those equations, you will see there is a triangular region on the left side of the first quadrant.
You have:
If you graph an shade the correct half-plane for those equations, you will see there is a triangular region on the left side of the first quadrant.
Answer:
x = ± 5
Step-by-step explanation:
Given
x² - 4x - 25 = - 4x ( add 4x to both sides )
x² - 25 = 0 ( add 25 to both sides )
x² = 25 ( take the square root of both sides )
x = ± = ± 5