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Tems11 [23]
3 years ago
11

Simplify -3i sqrt -40 Enter your answer in simplest radical form

Mathematics
1 answer:
Mariulka [41]3 years ago
6 0

Answer:

Step-by-step explanation:

-3i  √(-40) = -3i √40i²    ...(i² = - 1)

                 = -3i √40 i

              -3i  √(-40)  =   3√40

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Answer:

1: $11

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3: $128.57

Step-by-step explanation:

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43.19 • 3 = 128.57

8 0
3 years ago
Can someone help me please
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Answer:

A

Step-by-step explanation:

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2. A parking lot holds 40 cars. There are 20 cars in the lot already. Which inequality can be solved to show all the
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Answer:

perimeter = 6x + 15

Step-by-step explanation:

The perimeter of the triangle is the distance around the triangle.

We need to apply our ability to convert word problems in to mathematical expressions.

We were told that the bottom of the triangle is x units.

From the diagram perimeter 4x + 12 + x + 3 + x = 6x + 15

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4 0
2 years ago
Read 2 more answers
A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
guajiro [1.7K]

We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation A=45e^{-0.05t}.

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate A=15 and solve for t as:

15=45e^{-0.05t}

\frac{15}{45}=\frac{45e^{-0.05t}}{45}

\frac{1}{3}=e^{-0.05t}

Now we will switch sides:

e^{-0.05t}=\frac{1}{3}

Let us take natural log on both sides of equation.

\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})

-0.05t\cdot (1)=\text{ln}(\frac{1}{3})

-0.05t=\text{ln}(\frac{1}{3})

t=\frac{\text{ln}(\frac{1}{3})}{-0.05}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-5}

t=-\text{ln}(\frac{1}{3})\cdot 20

t=-(\text{ln}(1)-\text{ln}(3))\cdot 20

t=-(0-\text{ln}(3))\cdot 20

t=20\text{ln}(3)

Therefore, it will take 20\text{ln}(3) years for area of the glacier to decrease to 15 square kilo-meters.

6 0
3 years ago
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