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strojnjashka [21]
3 years ago
6

A train 375 m long is running at a speed of 45 km/hr.how long will it take to pass a single post

Mathematics
1 answer:
Kruka [31]3 years ago
4 0

we know that

The time it takes for the train to pass a single post is equal to the time it takes for the train to pass its length.

the length of the train is-----> 375 m

<u>convert to Km</u>

1 Km =1,000 m

375 m=375/1,000=0.375 Km

the speed of the train is 45 km/hour

so

by proportion

\frac{1}{45}\frac{hour}{Km} =\frac{x}{0.375}\frac{hour}{Km}\\ \\45*x=0.375\\ \\ x=0.375/45\\ \\x=0.0083\ hours

<u>convert to minutes</u>

1 hour=60 minutes

0.0083 hours=0.0083*60=0.5 minutes

<u>convert to seconds</u>

1 minute=60 sec

0.5 minutes=0.5*60=30 sec

therefore

<u>the answer is</u>

30 seconds

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ANSWER

14 \: ft



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l =  \sqrt{196.06}


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You have a biased coin for which p(h)=pp(h)=p. you toss the coin 2020 times. what is the probability that you observe 88 heads a
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Part A:

The probability of observing 8 heads and 12 tails is given by:

P(8)=\, ^{20}C_8p^8(1-p)^{20-8}=\, ^{20}C_8p^8(1-p)^{12}



Part B:

<span>You observe more than 8 heads and more than 8 tails, when you observe 9 heads and 11 tails, 10 heads and 10 tails, and 11 heads and 9 tails.

Therefore, the probability of </span><span>observing more than 8 heads and more than 8 tails</span> is given by:

P(9)+P(10)+P(11) \\  \\ =\, ^{20}C_9p^9(1-p)^{20-9}+\, ^{20}C_{10}p^{10}(1-p)^{20-10}+\, ^{20}C_{11}p^{11}(1-p)^{20-11} \\  \\ =\, ^{20}C_9p^9(1-p)^{11}+\, ^{20}C_{10}p^{10}(1-p)^{10}+\, ^{20}C_{11}p^{11}(1-p)^{9}
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A bulletin board has a perimeter of 200 inches. Which equation expresses the area A(w) of the bulletin board as a function of it
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Answer: A(W) = 100W -W^{2}

Step-by-step explanation:

The formula for calculating the perimeter is given as :

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The formula for the area is given as Length x width , substituting the values , we have :

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A = 100W -W^{2}

Therefore :

A(W) = 100W -W^{2}

6 0
3 years ago
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